Question

how many natural numbers lie between the squares of 89 and 100?​

Answer 1

Answer:

2079 natural numbers.

please mark as brainliest and follow me

Answer 2

Answer:

see the answer

Step-by-step explanation:

89^2= 7,921

100^2=10,000

Let,

a=7,921 (first term)

Since adjacent natural numbers differ by 1, they are in A.P.

So, d= common difference= 1

t=10000 (last term)

And n= no. of terms between 7,821 and 10,000

B/Q

t= a+(n-1)d [using nth term of an A.P.]

=>10000= 7921+ 1* (n-1)

=>2079= n-1

=>2080= n

Hence the required no. of natural no's. between the square of 89 and 100, I.e. 7921 and 10000 is 2080.

Hope this helps!!!

Thank you!!!

mark as branlist