Math, asked by chandan315, 10 months ago

How many number lying between 999 and 10000 can be
formed with the help of digits 0, 2, 3, 6, 7, 8 when the digits
are not repeated?
(a) 100 (b) 200 (c) 300 (d) 400

Answers

Answered by yogisistu1
0

Answer:

300

Step-by-step explanation:

removing all the odd numbers all the numbers total numbers are 600

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