How many number of atoms are present in 1.6gm Ozone
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2O3 -----> 3O2
So 96 g of o3 gives 3 mole of oxygen
1g of ozone gives 3 ÷ 96 mole of oxygen
1.6g of ozone gives 3 ×1.6÷ 96 moles of oxygen
Moles of oxygen = 0.05 mole
Number of oxygen atom = mole × Na
1 moles of oxygen has 2 oxygen atom
So 0.05 moles of oxygen have 2 × 0.05 atom of oxygen
Atom of oxygen = 0.1 atoms
This can be answer
But in avagadro number
It ans is
O.1 × 6.02× 10^ 23
0.602 × 10^ 23 = atom of oxygen
Hope it helps
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