Question

How many numbers are there from 300 to 425 which are divisible by both 4 and 8?

Answer 1

Hi Friend !!

Here's ur ans with solution :-


The number which is divisible by 4 and 8 will also divisible by 32.

So, the AP form is :-

320 , 352 , 384 ............ 416

First term ( a ) = 320

Common difference ( d ) = 32

Last term ( an ) = 416

• an = a + ( n - 1 )d

416 = 320 + ( n - 1 ) × 32

416 = 320 + 32n - 32

416 = 288 + 32n

128 = 32n

128 / 32 = n

4 = n

So , there are 4 number between 300 and 425 Which are divisible by 32 i.e, 4 and 8!!!