How many sides has a polygon the sum of whose interior angles is 1980°
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Answered by
15
(n-2)*180/n=1980
N-2/n=1980/180
N-2/n=11
N=11+2
N=13.
No. of sides=13
N-2/n=1980/180
N-2/n=11
N=11+2
N=13.
No. of sides=13
Answered by
9
Let nos. Of side be x
Sun of interior angle 180(x-2)
1980=180(x-2)
1980/180=x-2
11=x-2
11+2=x
13=x
Hence numbers of side is 13
Sun of interior angle 180(x-2)
1980=180(x-2)
1980/180=x-2
11=x-2
11+2=x
13=x
Hence numbers of side is 13
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