how many speheres of radius 2 cm can be formed by melting a ball of iron of radius 4cm? Also find the surface area of the spheres so formed
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4/3pi.r^3=4/3pi.r^3(x)
4×4×4=2×2×2(x)
64=8x
X=8
Ans.8 balls
4×4×4=2×2×2(x)
64=8x
X=8
Ans.8 balls
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Answered by
1
Small sphere:
r1=2cm
Ball:
r2=4cm
Number of small spheres · Volume of small sphere=Volume of ball
n · (4/3)·πr1^3=(4/3)·πr2^3
(4/3) and π gets canceled.
n·r1^3=r2^3
n=(r2^3)/(r1^3)
n=(4·4·4)/(2·2·2)
n=8
Surface area of 8 spheres=8·4·π·r^2
=8·4·(22/7)·2·2
=2816/7
=402.28 cm^2
=403 cm^2 [approximately]
r1=2cm
Ball:
r2=4cm
Number of small spheres · Volume of small sphere=Volume of ball
n · (4/3)·πr1^3=(4/3)·πr2^3
(4/3) and π gets canceled.
n·r1^3=r2^3
n=(r2^3)/(r1^3)
n=(4·4·4)/(2·2·2)
n=8
Surface area of 8 spheres=8·4·π·r^2
=8·4·(22/7)·2·2
=2816/7
=402.28 cm^2
=403 cm^2 [approximately]
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