How many spherical bullets can be made out of a solid cube of lead whose edge measures 44 cm, each bullet being 4cm in diameter ?
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FIRST WE FIND VOLUME OF BOTH BULLET AND THE CUBE OF LEAD
VOLUME OF BULLET=4/3πR³
=4/3×22/7×(2)³
=704
VOLUME OF CUBE LEAD=A³
=(44)³
=85184
NOW,
VOLUME OF CUBE/VOLUME OF BULLET=NO. OF BULLET
=85184/704
=121
NO. OF BULLET=121
VOLUME OF BULLET=4/3πR³
=4/3×22/7×(2)³
=704
VOLUME OF CUBE LEAD=A³
=(44)³
=85184
NOW,
VOLUME OF CUBE/VOLUME OF BULLET=NO. OF BULLET
=85184/704
=121
NO. OF BULLET=121
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