Question

how many terms are there in AP 41,38...5​

Answer 1

Solution:-

Given sequences

=> 41 , 38 , ........., 5

=> First term ( a ) = 41

=> Common difference ( d ) = 38 - 41 = - 3

=> Tₙ = 5

Formula

=> Tₙ = a + ( n - 1 )d

=> 5 = 41 + ( n - 1 ) × - 3

=> 5 = 41 - 3n + 3

=> 5 = 44 - 3n

=> 5 - 44 = - 3n

=> 39 = 3n

=> n = 39 / 3

=> n = 13

Number of term is 13