Math, asked by jprprabhakar896, 7 months ago

how many terms are there in the sequence 3,6,9,12.......11​

Answers

Answered by karunatrisal2003
0

Step-by-step explanation:

a= 3

d=a2-a1 =6-3=3

an=11

n=?

an=a+(n-1)d

11=3+(n-1)3

11=3+3n-3

11=3n

n=11/3

you can check it

an= a+(n-1)d

11=3+(11/3-1)3

11=3+(8/3)3

11=8+3

11=11

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