Question

how many terms of the AP 65 60 55 so on up to be taken so that the sum is zero

Answer 1

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Answer 2

FIRST TERM = 65

COMMON DIFFERENCE = - 5
$sum = \frac{n}{2} (2a + (n - 1)d) \\ 0 = \frac{n}{2} (130 - 5n + 5) \\ 0 = 130 - 5n + 5 \\ 0 = 135 - 5n \\ 5n = 135 \\ n = 27$
SUM OF AP 65, 60, 55 AND SO ON WILL EQUAL TO ZERO IF THEY ARE TAKEN UP TO 27.

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