How many three-digit numbers are divisible by 7?
Answers
Answered by
0
Answer:
a=105
an=994
d=7
we have,an=a+(n-1)d
=994=105+(n-1)7
=994-105=(n-1)7
=889/7=(n-1)
=127=n-1
n=127+
=128
therefore, 128 3 digit numbers can be divisible by 7
Answered by
0
Answer: The number of 3 digit numbers divisible by 7 are 128.
Step-by-step explanation: Take 1000 and divide it by 7 to know the last 3 digit number.
1000/7 = 142 ( don't take the reminder)
Now multiple the above quotient with 7 to know the last number.
142 × 7 = 994.
Take 100 and divide it by 7 to know the first 3 digit number.
100/7=14
Add one with the quotient and multiply it with 7.
(14+1)×7=105
Then use the formula An = A+(n-1)d
Where An=994,A=105,d=7,n=?
994=105+(n-1)7
889=(n-1)7
n-1=127
n=128
HOPE U UNDERSTOOD!!
Similar questions