How many ti les whose length and breath are
12 cm and 5cm respectively will be needed
to fit in a rectangulas region whose
length and breath are respectively.
(a) 200cm and 144cm
(b)80 cm and 48cm
Answers
Answer:
tiles,
l= 12 cm
b= 5 cm
perimeter = 2(l+b)
= 2(12+5)
= 2(17)
= 34 cm
Step-by-step explanation:
a) l= 200 cm
b = 144 cm
perimeter = 2(l+b)
= 2(200+144)
= 2(344)
= 688 cm
no of tiles = perimeter of rectangular region
perimeter of tiles
= 688
34
= 20
There are 20 tiles
b) l=80
b = 48
perimeter = 2(l+b)
= 2(80+48)
= 2(128)
= 256
no of tiles = perimeter of rectangular region
perimeter of tiles
= 256
34
= 7.5
There are 7.5 tiles