Question

each side of rhombus is 15 cm and the length of one of its diagonal is 24 cm the area of rhombus is​

Answer 1

second pic its correct solution

Answer 2

$\bf{\underline{Question:-}}$

each side of rhombus is 15 cm and the length of one of its diagonal is 24 cm the area of rhombus is.

$\bf{\underline{Given:-}}$

• Each side of rhombus = 15cm
• length of one it's diagonal is 24cm

• Area = ?

$\bf{\underline{Solution:-}}$

∆BPC is a right angled triangle

So,

By Pythagoras Thereom

$\bf → PC^2 = BC^2 - BP^2$

$\bf → PC^2 = 15^2 - 12^2$

$\bf → PC^2 = 225 - 144$

$\bf → PC^2 = 81$

$\bf → PC = \sqrt{81}$

$\bf → PC = 9cm$

AC diagonal = 2 × PC

Ac diagonal = 2 × 9 = 18cm

$\bf {\underline{Therefore:-}}$

Area of rhombus = 1/2 × AC × BD

Area = 1/2 × 18 × 24

Area = 1 × 18 × 12

Area = 216 $\sf cm^2$

$\bf{\underline{Hence:-}}$

• Area of rhombus = 216$\bf cm^2$