How many times does the digit 1 occur in ten's place in the numbers from 100 to 1000
Answers
Answered by
0
Answer:
Step-by-step explanation:
Basically we want to know how many numbers of 3 digits greater than 100 have 1 in the tens place (note that the upper limit has a 0 in that position).
This means the numbers are in the form a1b, where a and b are digits.
There is no restraint regarding b, so it can take 10 values. As for a, we know it cannot be 0, so it can take 9 values.
9×10=90
I hope it helps U
Answered by
0
Step-by-step explanation:
according to me 90 is the correct answer
Similar questions