How many vibration will a tuning fork of frequency 280hz complete during the time sound travel forward in air by 20m. take speed of sound in air as 340 m/s?
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Given:
Speed of sound=340m/s
Distance=20m
Speed =distance/time
time=distance/speed
time=20/340
=0.05sec
Frequency=280Hz
Frequency= No.of Vibrations in one second=280Hz
Therefore number of Vibrations completed in 0.05sec
=280x0.05=14 Vibrations
Speed of sound=340m/s
Distance=20m
Speed =distance/time
time=distance/speed
time=20/340
=0.05sec
Frequency=280Hz
Frequency= No.of Vibrations in one second=280Hz
Therefore number of Vibrations completed in 0.05sec
=280x0.05=14 Vibrations
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