How many ways are there for 8 men and 5 women to stand in a line so that no two women stand next to each other?
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Answer:
609638400
Step-by-step explanation:
Hence, we need to find how many ways we can arrange 5 women in the 9 possible (as shown above) places,this is actually 9P5=9∗8∗7∗6∗5=15120
Now applying the fundamental law of counting (precisely product rule), total number of possible arrangements satisfying both constraints is: 15120∗40320=609638400 which is your required/desired answer.
muqaddasishaq987:
but this ans is true for... as no two women stand next to each other,we can imagine the situation !
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