how many words can be formed by the letters of the word independence in how many of them the vowels do not occur together?
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Hiii frnds.......
INDEPENDENCE : N=3 D=2 E=4
Total permutation = 12!/ 3! 4! 2!
= 19958400/ 12
= 1663200
First, calculate for vowels occur together
:::::: 8!/3! 2! × 5!/4!
:::::: 16800
Vowels do not occur together
:::::: Total - vowels occur together
:::::: 1663200 - 16800
:::::: 1646400
Hope it helps....
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