Question

How much charge in faraday is required for reduction of 1 mole of Al3+ to Al?

Answer 1

Al³ + 3e will give u Al so for reduction of 1 mole Al³ need 3 mol electron i.e. 3 Faraday charge

Answer 2

Given,

1 mole of Al⁺³ is given.

To find,

We have to find the charge in faraday required for the reduction of Al⁺³ to Al.

Solution,

The charge required in faraday for the reduction of 1 mole of Al⁺³ to Al is 3F.

Now we can simply find the charge in faraday for the reduction of Al⁺³ to Al by calculating the charge lost by Al.

The charge lost by Al for the reduction of Al⁺³ to Al = Charge required in faraday for the reduction of 1 mole of Al⁺³ to Al.

The charge lost by Al for the reduction of Al⁺³ to Al = +3

Charge required in faraday for the reduction of 1 mole of Al⁺³ to Al  = 3F

Hence, the charge required in faraday for the reduction of 1 mole of Al⁺³ to Al is 3F.