Question

How much charge is required for the reduction of 1mol of MnO4 - to Mn2+?

Answer 1

oxidation state of Mn in MnO4- is +7

oxidation state of Mn^2+ is +2

(As concerntration of both are same 1:1 i.e. reactants and products no. of electrons required will be direct same as change of oxidation no.)

so change in oxidation state = +7 - (+2) = 5

hence we need 5 electrons to reduce Mno4- to Mn^2+

(i thought i will Mn^2+ so solved it like it if wrong let me know(

Answer 2

Here ^_^

Charge of Mn in

MnO−4 : +7 (maximum possible is +7 for Mn)

Mn2+ : +2

Difference in charge : −5

Hence 5 moles of electrons are required for 1 mole of MnO−4 .

Hope It is clear :)