Question

how much energy in joules is neccessary to rais the temp of 5 kg water from 20 to 100 degree

Answer 1

Answer:

The secret to this is in the constant called Specific Heat Capacity of Water, which is essentially 4.186 joules per gram, per °C.

Now, We have

5 kg of water = 5,000 gram of water

Temperature Difference = 100 °C - 20 °C = 80 °C

All you need to do is essentially multiply specific Heat Capacity with the two values above.

The magnitude of Heat in Joules =

(4.186 J / g °C) x (5,000 g) x (80 °C) = 1,674,400 Joules

You can convert this into Kilo Joules by dividing it with 1,000, and further into Mega Joules by dividing again with 1,000.

Explanation: