Question

How much heat is absorbed by 1.00x10 2g of ice at -33.0ºC to become water at 0.0ºC?

Answer 1

Answer:

33°C of heat is needed tomekt the it

Answer 2

Answer:

Explanation:

m = mass (in grams)

c = specific heat capacity (J/g°C)

ΔT = change in temperature (°C)

Here, we will use the specific heat capacity for liquid water which is 4.19 J/g°C.

The mass given is 25.0 grams.

As for the change in temperature, I will assume that it start off at room temperature, 25°C.

25°C−0°C

=25°C

Q=mcΔT

Q=25grams

⋅

4.19Jg°C

⋅25°C

Q=2618.75J

Take into account significant figures and the answer should be

2.6⋅103J