How much material required to wrap a cubical box of side 7.5
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Answered by
8
Answer:
material required to wrap a cubical box of side 7.5=6×7.5=45
Answered by
0
Answer:
we have to find the surface area of cube which is 6×side^2
=337.5unit^2.
Ans. 337.5unit^2 of material is required to wrap the cubical box.
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