how much maximum mass of aluminium can be obtained from 100g of AL2(SO4)3
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Molar mass of Al2(SO4)3 = 27×2 + 96×3
= 54+288 = 342
Thus, No. of moles of Al2(SO4)3 = 100/342
Hence, No. of moles of Al =
Thus , Max mass of Al = 0.584×27 = 15.768g ......ans...
= 54+288 = 342
Thus, No. of moles of Al2(SO4)3 = 100/342
Hence, No. of moles of Al =
Thus , Max mass of Al = 0.584×27 = 15.768g ......ans...
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