Question

How much metal sheet is required to make an open cylindrical tank of radius 4.2 m and height 15 m.

Answer 1

Radius=4.2m.
Height=15m.
Metal sheet required to make open tank=2πrh+πr×r
=πr(2h+r)
=22/7×42/10(2×15+4.2)
=13.2(30+4.2)
=13.2×34.2
451.44sq.m

Answer 2

Answer:

$Area \: of \: metal \: sheet \: required \\(A)=451.44 m^{2}$

Step-by-step explanation:

Dimensions of the open cylindrical tank:

Radius (r)=4.2 m

Height (h)=15 m

$Area \: of \: metal \: sheet \: required (A)\\=Lateral \: surface \:Area + base\: area\\=2\pi rh + \pi r^{2}\\=\pi r(2h+r)\\=\frac{22}{7}\times 4.2(2\times 15+4.2)\\=22\times 0.6(30+4.2)\\=22\times 0.6\times 34.2\\=451.44 m^{2}$

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