Question

if X + Y = 12 and X Y=14 find the value of (x² + Y²)

Answer 1

x+y=12
(x+y)²=12² ( squaring both side )
x²+y²+2xy=144
x²+y²+2(14)=144 (xy=14)
x²+y²=144-28
x²+y²=116

Answer 2

Hey there!!
we have ,

xy = 14

x +y = 12
${(x + y)}^{2} = {12}^{2} (squaring \: both \: the \: side) \\ \\ = > {x }^{2} + {y}^{2} + 2xy = 144 \\ \\ = > ({x}^{2} + {y}^{2} ) = 144 - 2 \times 14 \\ \\ = > {x}^{2} + {y}^{2} = 116$
Hope this helps u !!