Chemistry, asked by janhavi0405, 8 months ago

How much sugar(C12H22O11) will be required if each person on earth is given 100 molecules of sugar? (population of earth=3*10^10)​

Answers

Answered by llɱissMaɠiciaŋll
7

Explanation:

1015 x 3 x 1010 moles = 3 x 1025 moles of sugar per day

Gram Atomic Mass of 1 mole of sugar = 12 x 12 + 1 x 22 + 16 x 12

= 144 + 22 + 192

=358 g

Mass of 3 x 1025 moles of sugar = 3 x 1025 x 358 grams

= 1074 x 1025 grams

= 1074 x 1022 kg of sugar

So 1074 x 1022 kg of sugar would be required per day.

sugar would be required per day.

Answered by Anonymous
27

\huge\boxed{\fcolorbox{red}{blue}{ QUESTION }}

How much sugar(C12H22O11) will be required if each person on earth is given 100 molecules of sugar? (population of earth=3*10^10)

 \orange{\underline{\textit{\green{\bf{CONCEPT \:used:-}}}}}

IS OF MOLE :-

 \orange{\underline{\textit{\blue{\bf{DEFINITION:- }}}}}

The mole (symbol: mol) is the unit of measurement for amount of substance in the International System of Units (SI). A mole of a substance or a mole of particles is defined as exactly 6.02214076×10^23 particles, which may be atoms, molecules, ions, or electrons.

 \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

sugar(C12H22O11) required for each person on earth :-

GIVEN

  • 100 MOLECULES TO BE GIVEN TO EACH PERSON
  • POPULATION OF EARTH-->3 \times  {10}^{10}

 \orange{\underline{\textit{\</strong><strong>g</strong><strong>r</strong><strong>e</strong><strong>e</strong><strong>n</strong><strong>{\bf{</strong><strong>TOTAL\</strong><strong>:</strong><strong> MOLECULES </strong><strong>\</strong><strong>:</strong><strong>REQUIRED</strong><strong>:-</strong><strong>}}}}}

PER PERSON REQUIREMENT× POPULATION OF EARTH --->

100 \: molecules  \times 3 \times  {10}^{10}  \\  \\  3 \times  {10}^{12}  =  \: number \: of \: molecules \: required \: in \: total \:

SO ONE MOLE OF SUGAR WEIGHT 342 grams

one mole = 6.022 \times  {10}^{23}  \: molecules \: =342 grams

so one molecules weights -->

 \frac{342}{6.022 \times  {10}^{23} } \: grams

so 3×10^12 molecules weights -->

 \frac{342}{6.022 \times  {10}^{23} }  \times 3 \times  {10}^{12}  \:  \: grams

 \orange{\underline{\textit{\red{\bf{ </strong><strong>REQUIRED\</strong><strong>;</strong><strong> WEIGHT</strong><strong>}}}}}

\underline{\blue{170 \times  {10}^{ - 11}  \:  \: grams}}

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