Question

How much time would a
pedestrian, moving an average
of 4km/hr, take covering
distance of 900m.
a​

Answer 1

Answer:

Speed of A = 4km/h

Speed of B = 10km/h

Due to delay of 4 hours , A is 16 Km far from B.

And They move in same direction then Relative speed is 6km/h

Then Time is 16/6 which is 8/3

Then we find distance from B so Distance =speed × time

Distant =8/3 ×10=26.7 km

I hope you like it.

Answer 2

Answer:

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