Question

(पाठ देख)
Sum of the two numbers is 51. Tfone of the numbers exceed the other number by 11 then find
the product of the two numbers.
(See Lessons)
किसी समान्तर श्रेणी के तीन क्रमागत पदों का योग 42 है और उनका गुणनफल 2520 है। समान्तर
श्रेणी के पद ज्ञात कीजिए।
(पाढ7 देखें)​

Answer 1

Answer:

Let one number be x then the other number is x+11

Sum = 51

x + x + 11 = 51

2x = 51 - 11

2x = 40

x = 40/2 = 20

x + 11 = 20 + 11 = 31

The numbers are 20 and 31

Product = 20×31 = 620

Product of the two numbers is 620

Pls follow...

Answer 2

Answer:

Let two numbers be x & y

A.T.Q

x + y = 51 ------------- eq.1

& one no. exceed other by 11

y = x + 11 ------------- eq.2

putting eq. 2 in 1

x + x+ 11 = 51

2x = 40

x = 20

y = 20 + 11 => 31

their product = 20 × 31 => 620 AnS.