Physics, asked by dude7917, 11 months ago

How much work is done to carry 1 milicol coulomb charge from 25v to 125v.

Answers

Answered by sbtgta125

0

Answer:

0.1 Joule.

Explanation:

Work done = charge × potential difference

Work done = 1 × 10⁻³ × (125-25) = 10⁻¹ Joule.

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