How phenotypic ratio of dihybrid(medelian) cross can modify? explain????
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Answer:
Explanation:
Dihybrid (Mendelian) cross:
A dihybrid cross is made up of two individuals who have two features that are regulated by two different genes. Gregor Mendel's observation of pea plants that were either round or wrinkled, yellow or green, gave rise to the concept of a dihybrid cross. When two heterozygous people are crossed, the offspring's genotype and phenotypic ratios will be predictable. Crossing heterozygous parents would result in an estimated phenotypic ratio of 9:3:3:1. [1] Deviations from these predicted ratios may point to a relationship between the two features or to a non-Mendelian method of inheritance for one or both of the traits.
Phenotypic ratio of Dihybrid (Mendelian) cross:
A hybrid between two heterozygotes has a phenotypic ratio of 9:3:3:1, meaning that 9/16 of the individuals have the dominant phenotype for both characteristics, 3/16 have the dominant phenotype for one trait, 3/16 have the dominant phenotype for the other trait, and 1/16 are recessive for both traits.
Only applies to creatures that reproduce sexually, such as angiosperms. Mendel's laws must be observed for this to happen.
The following components make up the predicted phenotypic ratio of 9:3:3:1 is:
The number 9 denotes the percentage of people who exhibit both dominating traits: 1 x RRYY + 2 x RRYy + 2 x RrYY + 4 x RrYy.
The first three people are those who exhibit the first dominant characteristic and the second recessive trait, respectively: 1 x RRyy + 2 x Rryy.
The second three are those who exhibit both the first dominant and second recessive traits: 1 x rrYY + 2 x rrYy.
The homozygote, represented by the number 1, exhibits both recessive traits: 1 x rryy.
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