Question

how this sum must be done

Answer 1

= 27*27(-m)(-m)(-m)(-m)(-m)(n)(n) / 18*18*18*m*m*m*n

= -0.125*(m)^2*n

Hope it helped you

Answer 2

$<b><marquee>Here's your answer</marquee></b>$

$\tt\dfrac{27^2×+(-m)^5×n^2}{18^3×m^3×n}$

$\tt\dfrac{(3^3)^3×(-m)^5×n}{3^2×2}$

$\tt\dfrac{3×(-m)^2×n}{2}$

$\tt\dfrac{3m-^2n}{2}$=1.5m-²n

And always remember you should convert the complex no. in their simplest form such as 27 and 18 in this question

Hope it helps you :)


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