How to calculate allele frequencies by direct count?
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Gene counting method, as the name implies, is just counting the number of copies of the gene present in an individual and hence a population/study group. In a diploid organism, like humans, the gene counting is done by first assigning the genotype to every sample. All the gene count in a homozygote is 2 while in a heterozygote is 1 for each gene. So if you have two alleles A and B, then gene count for:
the homozygote AA is 2A and
BB is 2B and
heterozygote AB is 1A+1B.
If a population/group of 100 individuals (total chromosomes/gene copies = 100x2=200, diploid genome) have 70AA, 10AB and 20BB then the gene count is:
Count of A = 2x70+10 = 150
Count of B = 2x20+10 = 50
This is an easy way to see if there are any differences in the frequencies of the alleles between groups. In the above example the group had an excess of A compared to B.
the homozygote AA is 2A and
BB is 2B and
heterozygote AB is 1A+1B.
If a population/group of 100 individuals (total chromosomes/gene copies = 100x2=200, diploid genome) have 70AA, 10AB and 20BB then the gene count is:
Count of A = 2x70+10 = 150
Count of B = 2x20+10 = 50
This is an easy way to see if there are any differences in the frequencies of the alleles between groups. In the above example the group had an excess of A compared to B.
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