How to calculate no of atom of carbon hydrogen and oxygen in 6.84 milligram of sucrose
Answers
We have to calculate the no of atoms of carbon, hydrogen and oxygen in 6.84 milligram of sucrose.
solution : chemical formula of sucrose is C₁₂H₂₂O₁₁ . it is also known as common sugar and is widely used in our life.
molecular mass of sucrose = 342 g/mol
given mass of sucrose = 6.84 mg
so no of moles of sucrose = (6.84 × 10¯³g)/(342g/mol)
= 2 × 10¯⁵ mol
no of molecules of sucrose = no of moles of sucrose × Avogadro's number
= 2 × 10¯⁵ × 6.023 × 10²³
= 12.046 × 10^18
= 1.2046 × 10^19
we see, in one molecule of sucrose, 12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms are present.
so, no of oxygen atoms in 1.2046 × 10^19 molecule of sucrose = 11 × 1.2046 × 10^19
= 13.2506 × 10^19 = 1.32506 × 10²⁰
similarly, no of hydrogen atoms = 22 × 1.2046 × 10^19 = 26.5012 × 10^19 = 2.65012 × 10²⁰
no of carbon atoms = 12 × 1.2046 × 10^19
= 14.4552 × 10^19 = 1.44552 × 10²⁰
Answer:
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