How to calculate no. of atoms present in sulphur of 6.4g??
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NUMBER OF MOLES = WEIGHT/ATOMIC WEIGHT
= 6.4/32
= 0.2MOLE.
1MOLE = 6.O23×10²³ALOM
∴, 0.2MOLE = 0.2×6.023×10²³ATOM
= 1.2046×19²³ATOM
I HOPE IT HELPS U
= 6.4/32
= 0.2MOLE.
1MOLE = 6.O23×10²³ALOM
∴, 0.2MOLE = 0.2×6.023×10²³ATOM
= 1.2046×19²³ATOM
I HOPE IT HELPS U
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