Biology, asked by yadavajit6253, 1 year ago

how to calculate weight percent of oxygen in BaNi0.5Nb0.5O3

Answers

Answered by Raju2392

Ethanol=C2H5OH

C2= 2*12

H5=5*1

O=16

H=1

24+5+16+1= 46g/mole

Carbon= (24/46)*100= 52.2%

Hydrogen= 5+1=6 (6/46)*100= 13.0%

Oxygen= (16/46)*100= 34.8%

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