Question

How to construct 150 degree angle with compass

Answer 1

HEY MATE HERE IS YOUR ANSWER

.Take a line segment, say, AB.

Choose a point C on it.

With center C, and radius BC, draw an arc.

With center B and radius BC, cut the previous arc at say DD. (∠DCB=60∘∠DCB=60∘because we just made CD=BC=BD .)

With center D, and radius BC draw an arc.

With center B and radius BC, cut this arc at, say, EE. Then EC is the bisector of ∠BCD, and hence ∠BCE=30∘

.Then, ∠ACE=180∘−∠BCE=150∘.

HOPE THIS HELPS YOU......✌✌

Answer 2

Step 1: Compute how 150 can be expressed

$150^o= 180^o-30^o$  

30 degrees is half of 60 degrees which is an angle of equilateral triangle

Step 2: Draw a line segment AB

Step 3: Choose a point C on AB and with BC as radius and centre as C, draw an arc. Again, with same radius but centre as B, draw another arc such that it cuts the previous arc at D. Now as BC=CD=BD, hence angle DCB would be $60^o$

Step 4: Draw an arc with centre as D and radius as BC. Draw another arc with same radius but centre as B such that it cuts the previous arc at E. This will make EC the bisector of the angle BCD. Hence angle BCE is $30^o$

So, angle ACE of 150 degrees is constructed.