how to count no of sigma and pi bond ,please see question no 1
Answers
first make structure of given molecule and show charge carefully and count no of bonds
as sigma bond is formed by head to head overlapping of orbital and pi bond is formed by sidewise overlapping
1. there two pi bonds and one sigma bond in N2. .
reason (not confirmed) : N2 is fairly simple; since nitrogen is atomic number 7, it has an electron configuration of 1s22s22p3
, so it favorably shares its three 2
p electrons with three other 2
p electr.ons from another nitrogen to form a noble gas configuration ( 1s22s22p6).
Since all three
2p orbitals participate, we form one 2pz−2pz head-on (σ) interaction, one 2px−2px sidelong (π) interaction, and one 2py−2py sidelong (π) interaction.
Thus, we form a triple bond, which consists of the one (σ
) and two( π) bonds we just mentioned. The remaining two lone pairs of electrons are stored in each nitrogen's 2
s orbital. So, we get the following structure that illustrates this discussion:
3. O2 has 1 sigma bond and 1 pi bond.
reason : the O2 molecule's Lewis structure shows a double bond between the two oxygen atoms. Always remember that a double bond is comprised of 1 sigma bond and 1 pi bond. A triple bond has 1 sigma and 2 pi bonds.