Question

How to determine whether the force is 'Attractive' or 'Repulsive' using Coulomb's Law??

Answer 1

Coulomb’s law establishes that,
The force exerted by two charges between each other is proportional to the product of the charge values and is inversely proportional to the square of the distance between them.

F⃗ ∝q1q2r2

F⃗ = Kq1q2r2

The constant of proportionality K is determined to be K = 14πε0

Thus,

F⃗  = 14πε0q1q2r2r^

Also, 14πε0 = 8.99×109Nm2C2
And, ε0 = 8.85×10−12C2Nm2

ϵ0 is known as the permittivity constant of free space.

The sign of force determines the whether the force is attractive or repulsive. Since, unlike charges attract, the sign is given as negative. A positive sign of force suggests a repulsive force since like charges repel. The direction of force is along the line separating the charges, i.e., it is along the vector r⃗ .

in this way it we can check the force is attractive or repulsive.

Answer 2

Explanation:

A positive sign of force suggests a repulsive force since like charges repel. The direction of force is along the line separating the charges, i.e., it is along the vector r⃗ . in this way it we can check the force is attractive or repulsive