How to do find the angle in it??
Attachments:
Answers
Answered by
1
Hlo friend.. Cutiepie Here.
Here is ur answer :
➡️Given
angle APB = 120
angle PBC = 15
➡️To find
angle ADB
Solution
APC is a line .
angle APB + angle CPB = 180 ( Linear pair )
120 + angle CPB = 180
angle CPB = 180 - 120 = 60
In Triangle BCP
angle BCP + angle CPB + angle CBP = 180 ( Angle sum property)
Angle BCP+ 60 + 15= 180
Angle BCP + 75 = 180
angle BCP = 180 - 75
angle BCP = 105
angle BCA = angle ADB ( Angle in same segment)
angle ADB = 105°
( angle BCA = 105° )
____________
HOPE IT HELPS YOU..
Here is ur answer :
➡️Given
angle APB = 120
angle PBC = 15
➡️To find
angle ADB
Solution
APC is a line .
angle APB + angle CPB = 180 ( Linear pair )
120 + angle CPB = 180
angle CPB = 180 - 120 = 60
In Triangle BCP
angle BCP + angle CPB + angle CBP = 180 ( Angle sum property)
Angle BCP+ 60 + 15= 180
Angle BCP + 75 = 180
angle BCP = 180 - 75
angle BCP = 105
angle BCA = angle ADB ( Angle in same segment)
angle ADB = 105°
( angle BCA = 105° )
____________
HOPE IT HELPS YOU..
Similar questions