Math, asked by Nishitha0603, 10 months ago

how to factorize a^2 - a - 10 = 0

Answers

Answered by abdul9838
1

 \small \bf \pink{hey \: mate \: here \: is \: ur \: ans} \\  \\  \small \bf \pink{ \huge \: solution} \\  \\  \small \bf \pink{ {a}^{2}  - a - 10 = 0} \\  \\  \small \bf \pink{ \underline{ \underline{step \: by \: step \: explaination}}} \\  \\  \small \bf \pink{method = completing \: square \: method} \\  \\  \small \bf \pink{( {a)}^{2}  - 2 \times a \times  \frac{1}{2} +  { (\frac{1}{2} )}^{2} -  {( \frac{1}{2}) }^{2}   - 10 = 0} \\  \\  \small \bf \pink{(a -  \frac{1}{2} )^{2}  -  \frac{1}{4}  - 10 = 0} \\  \\  \small \bf \pink{(a -  \frac{1}{2} )^{2}  - \frac{ 1 - 40}{4}   = 0} \\  \\  \small \bf \pink{(a -  \frac{1}{2} )^{2}  -  \frac{41}{4}  = 0} \\  \\  \small \bf \pink{(a -  \frac{1}{2} ) ^{2}  =  \frac{41}{4} } \\  \\  \small \bf \pink{a -  \frac{1}{2}  =  \pm \sqrt{ \frac{41}{4} } } \\  \\  \small \bf \pink{a =  \frac{ \sqrt{41} }{2}  +  \frac{1}{2} } \\  \\  \small \bf \pink{a =  \frac{1 +  \sqrt{41} }{2} } \\  \\  \small \bf \pink{and \: } \\  \\  \small \bf \pink{a =  \frac{1 -  \sqrt{41} }{2}  \:  \:  \: ans}


Nishitha0603: just asked you to solve it
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Nishitha0603: yeh !
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