Math, asked by ajinkya1289, 1 year ago

how to find its answer

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Answered by rajeev378
4
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Here is your answer
3 \sqrt{48}  -  \frac{5}{2}  \sqrt{ \frac{1}{3} }  + 4 \sqrt{3}  \\  = 3 \sqrt{16 \times 3}  + 4 \sqrt{3}  -  \frac{5}{2 \sqrt{3} }  \\  = 3 \times 4 \sqrt{3}  + 4 \sqrt{3}  -  \frac{5}{2 \sqrt{3} }  \\  = 12 \sqrt{3}  + 4 \sqrt{3}  -  \frac{5}{2 \sqrt{3} }  \\  = 16 \sqrt{3}  -  \frac{5}{2 \sqrt{3} }  \\  =  \frac{(32 \times 3 ) - 5}{2 \sqrt{3} }  \\  =  \frac{96 - 5}{2 \sqrt{3} }  \\  =  \frac{91}{2 \sqrt{3} }   \\  =  \frac{91 \sqrt{3} }{2 \sqrt{3} \times  \sqrt{3}  }  \\  =  \frac{91 \sqrt{3} }{2 \times 3}  \\  =  \frac{91 \sqrt{3} }{6}

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