Question

plss slove this maths problem

Answer 1

Step-by-step explanation:

We know that cosec²θ - cot²θ = 1

On cubing both sides, we get

⇒ (cosec²θ - cot²θ)³ = (1)³

(a-b)³ = a³ - b³ - 3ab(a - b)

⇒ cosec⁶θ - cot⁶θ - 3cosec²θcot²θ(cosec²θ - cot²θ) = 1

⇒ cosec⁶θ = 1 + cot⁶θ + 3cosec²θcot²θ(1)

⇒ cosec⁶θ = cot⁶θ + 3cot²θcosec²θ + 1.

Hope it helps you,

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