How to find out oxidation no. Of central metal atom?
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First of all, Oxidation number is the imaginary charge which appears on an atom in combined state due to electronegativity difference or a real charge on monoatomic ion
Now, let us consider some coordinate complex-
First of all, Oxidation number is the imaginary charge which appears on an atom in combined state due to electronegativity difference or a real charge
- [Mn(CO)5] : CO ( Carbonyl) is a neutral ligand and complex is also neutral. We need to find oxidation state of Mn so let it be x then x +5(0)=0 ie, x=0
- [NiCl4]2- : Cl is a negatively charged ligand and complex is anionic as it it is negatively charged. So to find oxidation state of Ni again let oxidation state of Ni be x; so x+4(-1)=-2 ie, x=+2
- [Ti(H2O)6]3+ : H2O is a neutral ligand and the complex is positively charged hence a cationic complex. Again, x+6(0)=+3 ie, x=-3
- [Ni(en)2]+2 : en (ethylenediamine) is a bidentate neutral ligand and the complex is cationic. In this case, it would be x+2 (0) =+2 ie, x=+2.
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