Question

how to find the 20 term of an ap given above.​

Answer 1

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Answer 2

Answer:

S14 = 1050

a = 10

Sn = n/2 [2a + (n - 1)d ]

S14 = 14/2 [2(10) + (14 - 1)d]

1050 = 7 [ 20 + 13d ]

150 = 20 + 13d

150 - 20 = 13d

130 = 13d

d = 10

Now,

a20 = a + 19d

= 10 + 19(10)

= 10 + 190

= 200