Question

obtain the values of the following 1) 10p3​

Answer 1

Answer:

$\huge{\mathcal{\red{ITZ SWAGAT}}}$

Answer 2

The value of ${}^{10}P_{3}$ is $720$.

Concept that we must know:

Before we find the value of ${}^{10}P_{3}$, let us know that value of ${}^{n}P_{r}$ first:

$\quad \boxed{{}^{n}P_{r}=\dfrac{n!}{(n-r)!}}$

Step-by-step explanation:

Now, ${}^{10}P_{3}$

$=\dfrac{10!}{(10-3)!}$

• since $n=10,r=3$

$=\dfrac{10!}{7!}$

$=\dfrac{10\times 9\times 8\times 7!}{7!}$

• here we have used the expansion for factorial $n$, that is
• $n!=(n-1)(n-2)(n-3)...(n-r)...1$

$=10\times 9\times 8$

$=\bold{720}$