Math, asked by Gimmeanswers, 1 year ago

How to find the least number which when divided by 12, 15, 18 , and 30 gives the remainder 6,9,12, and 24, respectively

Answers

Answered by rounakshaw23
0
Let the quotient be x
as we know that : divisor * quotient + remainder = dividend
and here the dividend is the least no. which we need to find
so now
we can write
(12*x+6)/(15*x+9) = (18*x+12)/(30*x+24) [all these are in proportion as on solving all the numerator and denominator will give the same dividend ]
on solving 
we get,
x = -1 , -2/5 [you must know solving quadratic equations to solve this sum]
you can place the value of x in any of the 4 binomial being formed
Thus, dividend(which is the least no. we need to find) = 12*x+6
                                                                                           = 12*(-1)+6
                                                                                           = -6
                                            or
     least no. = 12*x+6
                    = 12*(-2/5)+6 = 1.2 or simply 6/5
[we had two values of x so we got 2 anss for this Qs.]
but neglect ans = -6 
therefore 
the least no = 1.2 (ANS)

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