solve this please! :) will be very grateful!
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kelly3:
Hi It will be solved by congruence rules
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Answered by
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In triangle AOC and BOD
1. AO = BO{given}
CO = DO{given}
angle C = angle D {angles opposite to equal sides are equal}
HENCE,
triangle AOC = triangle BOD (CPCTC).
1. AO = BO{given}
CO = DO{given}
angle C = angle D {angles opposite to equal sides are equal}
HENCE,
triangle AOC = triangle BOD (CPCTC).
thanksie :D
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for that i would be grateful :D
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what should i mean this
yes or no
nothing, u can mean it as a smiley :)
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Answered by
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Given -
In ∆ AOC and ∆ BOD
AO = BO
CO=DO
To Prove -
(I) ∆AOC Congruent to ∆BOD
In ∆AOC and ∆BOD
AO = BO (given)
Angle AOC = Angle BOD (Vertically Opposite Angles)
CO = DO (given)
=> ∆AOC is Congruent to ∆BOD ( By SAS criteria)
____________
(ii) AC = BD
We have proved that ∆AOC is Congruent ∆BOD
=> AC = BD ( CPCT )
____________
(iii) AC || BD
Since , ∆AOD is Congruent to ∆BOD ,
=> angle ACO = Angle BDO ( CPCT)
=> Angle ACO and ∆BDO are interior alternate angles formed by Transversal CD
=> AC||BD
_______________________________
In ∆ AOC and ∆ BOD
AO = BO
CO=DO
To Prove -
(I) ∆AOC Congruent to ∆BOD
In ∆AOC and ∆BOD
AO = BO (given)
Angle AOC = Angle BOD (Vertically Opposite Angles)
CO = DO (given)
=> ∆AOC is Congruent to ∆BOD ( By SAS criteria)
____________
(ii) AC = BD
We have proved that ∆AOC is Congruent ∆BOD
=> AC = BD ( CPCT )
____________
(iii) AC || BD
Since , ∆AOD is Congruent to ∆BOD ,
=> angle ACO = Angle BDO ( CPCT)
=> Angle ACO and ∆BDO are interior alternate angles formed by Transversal CD
=> AC||BD
_______________________________
thanks a lot , zeroooo!!!!!
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