How to find the least number which when divided by 12, 15, 18 , and 30 gives the remainder 6,9,12, and 24, respectively
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Answered by
27
In this type of questions , we first find LCM of given numbers and then subtract common value to get the answer.
The LCM of 12 , 15,18 and 30=180. We want the answer 6,9,12 and 24. Now the difference is 6 in each case 12-6=6, 15-6=9,18-6=12 and 30-6=24 .
So, we have to subtract 6 from the LCM→180-6=174
So, (180-6=174) will have remainder of 6,9,12,24 when divided by 12,15,18 and 30 respectively.
hope it helps.....
The LCM of 12 , 15,18 and 30=180. We want the answer 6,9,12 and 24. Now the difference is 6 in each case 12-6=6, 15-6=9,18-6=12 and 30-6=24 .
So, we have to subtract 6 from the LCM→180-6=174
So, (180-6=174) will have remainder of 6,9,12,24 when divided by 12,15,18 and 30 respectively.
hope it helps.....
ranjanakaupranjana:
if it helps then mark brainliest please.......
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6
Answer:
(180-6=174) will have remainder of 6,9,12,24 divided by 12, 15, 18, and 30 respectively
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