How to find the perimeter of triangle with the vertices (0,2) (0,0) (1,0)
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Perimeter of triangle = Sum of all sides
= A+B+C
= 2+1+( (2)²+(1)²). (A=2,B=1)
= 3+3
= 9
= A+B+C
= 2+1+( (2)²+(1)²). (A=2,B=1)
= 3+3
= 9
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