Question

how to find value of x if 2^x+1 +3.2^x-3=76​

Answer 1

Answer:

hope it helps...........

Answer 2

Therefore the value of x is '5'.

Given:

Equation: $2^x^+^1 + 3(2^x^-^3) = 76$

To Find:

The value of 'x'.

Solution:

The given question can be solved very easily as shown below.

Given equation:  $2^x^+^1 + 3(2^x^-^3) = 76$

⇒ $2^x * 2^1 + 3(2^x*2^-^3 ) = 76$

⇒$2^x [ 2 + 3/8 ] = 76$

⇒ $2^x [ 19/8 ] = 76$

⇒ $2^x = 76*8/19$

⇒ $2^x = 4 * 8$

⇒ $2^x = 2^2*2^3 = 2^(^2^+^3^)=2^5$

As bases are equal powers must be equal.

So x = 5

Therefore the value of x is '5'.

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