Math, asked by jematiyogita, 10 months ago

how to find value of x if 2^x+1 +3.2^x-3=76​

Answers

Answered by akepati007
2

Answer:

hope it helps...........

Attachments:
Answered by SteffiPaul
0

Therefore the value of x is '5'.

Given:

Equation: 2^x^+^1 + 3(2^x^-^3) = 76

To Find:

The value of 'x'.

Solution:

The given question can be solved very easily as shown below.

Given equation:  2^x^+^1 + 3(2^x^-^3) = 76

2^x * 2^1 + 3(2^x*2^-^3 ) = 76\\

2^x [ 2 + 3/8 ] = 76

2^x [ 19/8 ] = 76

2^x = 76*8/19

2^x = 4 * 8

2^x = 2^2*2^3 = 2^(^2^+^3^)=2^5

As bases are equal powers must be equal.

So x = 5

Therefore the value of x is '5'.

#SPJ2

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